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2m^2-1m-24=0
a = 2; b = -1; c = -24;
Δ = b2-4ac
Δ = -12-4·2·(-24)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{193}}{2*2}=\frac{1-\sqrt{193}}{4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{193}}{2*2}=\frac{1+\sqrt{193}}{4} $
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